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What is the force in pounds exerted upwards on a piston with a diameter of 4 inches if a
gauge indicates the internal pressure in the cylinder is 1000 psi?

Répondre :

Peterachina61ask

Explications:

A =π *25/4

= 490.9mm

p= 100kpq

f=p*A=100*1000*0.0004909

= 49.09N

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