Dbz94200ask
résolu

(x+3)(2x-1)-5(2x+8)=

(3x-1)(4x+3)+(2x+2)(x-6)=

(9x+5)(x+6)-(8x-3)(4x+5)=

Répondre :

JULIE07ask

(2x²-x+6x-3)-10x-40= 2x²+5x-3-10x-40= 2x²-5x-43

 

Sevdan1991ask

(x+3)(2x-1)-5(2x+8)= 2x²-x+6x-3-10x-40=2x²-5x-43

(3x-1)(4x+3)+(2x+2)(x-6)= 12x²+9x-4x-1+2x²-12+2x-12=14x²+7x-13

(9x+5)(x+6)-(8x-3)(4x+5)=9x²+54x+5x+30-(32x²+40x-12x-15)=9x²+54x+5x+30-32x²-40x+12x+15=41x²+31x+45

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