résolu

factoriser:
(a−4)²​​ −(a−6)²

(1−​6/7 )​²​​−(−10−6/7 )²
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merci d'avance
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Inequationask

Bonsoir

Factoriser:

(a−4)²​​ −(a−6)²= (a-4-a+6)(a-4+a-6)= 2(2a-10)= 4(a-5)

(1−​6/7 )​²​​−(−10−6/7 )²= (1-6/7 -(-10-6/7 )(1-​6/7 +(-10-6/7 )

                                = (1-6/7 +10+6/7 )(1-​6/7 -10-6/7 )

                                = [(1*7-6+7*10+6)/7 ] [ (1*7-6-7*10-6)/7 ]

                                = (11)(-75/7)= -825/7

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