bonjour
x² + 3 x + 2
Δ = 9 - 4 ( 1 * 2) = 9 - 8 = 1
x 1 = ( - 3 - 1 ) / 2 = - 2
x 2 = ( - 3 + 1 ) / 2 = - 1
( x + 2 ) ( x + 1 )
Bonjour,
factoriser:
x²+3x+2
a= 1 , b= 3 et c= 2
delta= b²-4ac= (3)²-4(1)(2)= 1 donc > 0 alors 2 solutions
x1= (-3-1)/2= -2
x2= (-3+1)/2= -1
donc x²+3x+2 = (x+1)(x+2)
