bonjour
courbe f 1
f ( 0) = 0 et f ( 6) = 4
courbe linéaire f (x) = 4/6 = 2 /3 = 2 x /3
courbe f 2
f ( 0) = - 1 et f ( 4) = 5
( 5 + 1 ) / ( 4 - 0 ) = 6/4 = 3 /2 donc ax = 3 x / 2
f ( 0) = - 1 donc b = - 1
f (x) = 3 x /2 - 1
courbe f 3
f ( 0) = 2 et f ( 4) = - 2
( - 2 - 2 ) / ( 4 - 0) = - 4 /4 = - 1 donc ax = - x
f ( 0) = 2 donc b = 2
f (x) = - x + 2
courbe f 4
courbe constante k = 2
