Réponse :
f (x)=(−2x+3)+(2−3x) = −2x+3+2−3x = −5x+5
f (x)=(−2x+3)−(2−3x) = −2x+3−2+3x = x+1
f (x)=(−2x+3)(2−3x) = −2x*2+(−2x)*(−3x)+3*2+3*(−3x) = 6x²−4x−9x+6 = 6x²−13x+6
f (x)=3x(−2x+3)−2x(2−3x) = (3x*(−2x)+3x*3)−(2x*2−2x*(−3x)) = (−6x²+9x)−(4x+6x²) = −6x²+9x−4x−6x² = 5x